Selina solutions

Selina solutions

Grade 6

Properties of Angles and Lines (Including Parallel Lines) | Exercise 25(C)

Question 1

Q1)

In your note-book copy the following angles using ruler and a pair compass only.

Solution:

(i) Steps of construction

  1. At point Q, draw line QR = OB
  2. With O as centre, draw an arc of any suitable radius, to cut the arms of the angle at C and D
  3. With Q as centre, draw the arc of the same size as drawn for C and D. Let this arc cuts line QR at point T.
  4. In your compasses, take the distance equal to distance between C and D and then with T as centre, draw an arc which cuts the earlier arc at S.
  5. Join QS and produce up to a suitable point P. ∠PQR so obtained is the angle equal to the given ∠AOB

(ii) Steps of construction:

  1. At t point E, drawn line EF.
  2. With E as centre, draw an arc of any suitable radius, to cut the arms of the angle at C and D.
  3. With Q as centre, draw the arc of the same size as drawn for C and D. LEt this arc cuts line QR at point T.
  4. In your compasses take the distance equal to distance between C and D and then with T as centre, draw an arc which cuts the earlier arc at S.
  5. Join QS and produce up to a suitable point R ∠PQR so obtained is the angle equal to the given ∠DEF

(iii) Steps for construction :

  1. At point A draw line AB = QP
  2. With Q as centre, draw an arc of any suitable radius, to cut the arms of the angle A + C and D.
  3. With A as centre draw the arc of the same size as drawn for C and D. Let this arc cuts line AB at D.
  4. In your compasses take the distance equal to distance between 7 and 5 ; and then with D as centre, draw an arc which cuts the earlier arc at E.
  5. Join AE and produced upto to a suitable point C. ∠BAC so obtained is the angle equal to given ∠PQR

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subject-cta

Question 1

Q1)

In your note-book copy the following angles using ruler and a pair compass only.

Solution:

(i) Steps of construction

  1. At point Q, draw line QR = OB
  2. With O as centre, draw an arc of any suitable radius, to cut the arms of the angle at C and D
  3. With Q as centre, draw the arc of the same size as drawn for C and D. Let this arc cuts line QR at point T.
  4. In your compasses, take the distance equal to distance between C and D and then with T as centre, draw an arc which cuts the earlier arc at S.
  5. Join QS and produce up to a suitable point P. ∠PQR so obtained is the angle equal to the given ∠AOB

(ii) Steps of construction:

  1. At t point E, drawn line EF.
  2. With E as centre, draw an arc of any suitable radius, to cut the arms of the angle at C and D.
  3. With Q as centre, draw the arc of the same size as drawn for C and D. LEt this arc cuts line QR at point T.
  4. In your compasses take the distance equal to distance between C and D and then with T as centre, draw an arc which cuts the earlier arc at S.
  5. Join QS and produce up to a suitable point R ∠PQR so obtained is the angle equal to the given ∠DEF

(iii) Steps for construction :

  1. At point A draw line AB = QP
  2. With Q as centre, draw an arc of any suitable radius, to cut the arms of the angle A + C and D.
  3. With A as centre draw the arc of the same size as drawn for C and D. Let this arc cuts line AB at D.
  4. In your compasses take the distance equal to distance between 7 and 5 ; and then with D as centre, draw an arc which cuts the earlier arc at E.
  5. Join AE and produced upto to a suitable point C. ∠BAC so obtained is the angle equal to given ∠PQR

Still have questions? Our expert teachers can help you out

Book a free class now

Want to top your mathematics exam ?

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Book a free class now
subject-cta
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