Selina solutions

Selina solutions

Grade 6

Angles (With their Types) | Revision Exercise

Question 12

Q12)

Use the adjoining figure to find :

(i) ∠BOD

(ii) ∠AOC

Solution:

\angle AOD=72°

\angle BOC=64°

But sum of angles on the same side of a line = 180°

\angle AOD+\angle COD+\angle BOC=180°

72° +\angle COD+64° =180°

=180° - 136° +44°

(i) Now \angle BOD=\angle BOC+\angle COD

=64° + 44° =108°

(ii) \angle AOC=\angle AOD+\angle COD

=72° + 44° =116°

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Question 12

Q12)

Use the adjoining figure to find :

(i) ∠BOD

(ii) ∠AOC

Solution:

\angle AOD=72°

\angle BOC=64°

But sum of angles on the same side of a line = 180°

\angle AOD+\angle COD+\angle BOC=180°

72° +\angle COD+64° =180°

=180° - 136° +44°

(i) Now \angle BOD=\angle BOC+\angle COD

=64° + 44° =108°

(ii) \angle AOC=\angle AOD+\angle COD

=72° + 44° =116°

Still have questions? Our expert teachers can help you out

Book a free class now

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subject-cta
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