Selina solutions

# Question 10

Q10)

Find the angle formed by the arms of a clock at:

(i) 3 O’clock

(ii) 6 O’clock

(iii) 9 O’clock

(iv) 12 O’clock

Solution:

We know that sum of angles at a point= 360°

and on the face of a clock there are 12 marks on it.

(i) Now at 3 O'clock, the hour hand is on 3 while minute hand is at 12

Angle between them= \frac{3}{12}x 360° = 3 x 30° = 90°

(ii) At 6 O'clock, hour hand is at 6 and minute hand in at 12

Angle between them =\frac{6}{12}x 360°= 180°

(iii) At 9 O'clock, hour hand is at 9 and minute hand is at 12

Angle between them = \frac{9}{12}x 360° =270°

(iv) At 12 O'clock, hour hand and minute hand are both on 12°

Angle between them = \frac{12}{12}x 360° =360°

or 0° as both hands coincide each other.

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