Selina solutions

Selina solutions

Selina solutions

Grade 6

CHAPTERS

1. Number System (Consolidating the Sense of Numberness)

3. Numbers in India and International System (With Comparison)

5. Natural Numbers and Whole Numbers (Including Patterns)

6. Negative Numbers and Integers

12. Proportion (Including Word Problems)

17. Idea of Speed, Distance and Time

18. Fundamental Concepts (Algebra)

19. Fundamental Operations (Related to Algebraic Expressions)

20. Substitution (Including Use of Brackets as Grouping Symbols)

21. Framing Algebraic Expressions (Including Evaluation)

22. Simple (Linear) Equations (Including Word Problems)

23. Fundamental Concepts (Geometry)

25. Properties of Angles and Lines (Including Parallel Lines)

26. Triangles (Including Types, Properties and Construction)

30. Revision Exercise on Symmetry (Including Constructions on Symmetry)

32. Perimeter and Area of Plane Figures

Q13)

In the given figure :

(i) If ∠AOB = 45°, ∠BOC = 30° and ∠AOD= 110°;

find : angles COD and BOD.

(ii) If ∠BOC = ∠DOC = 34° and ∠AOD = 120° ;

find : angle AOB and angle AOC.

(iii) If ∠AOB = ∠BOC = ∠COD = 38°

find : reflex angle AOC and reflex angle AOD.

Solution 13:

(i) \angle COD=\angle AOD-\angle AOC

=\angle AOD-\left(\angle AOB+\angle BOC\right)

=110° -(45° +30°)

=110°-75°=35°

\angle BOD=\angle AOD-\angle AOB

=110°-45°

=65°

(ii) \angle AOB=\angle AOD-\angle BOD

=\angle AOD-\left(\angle BOC+\angle COD\right)

=120° - (34°+34°)

=120° -68°

=86°

(iii) Reflex \angle AOC=360° - \angle AOC

=360° - \left(\angle BOC+\angle COD\right)

=360° -(38° +38°)

=360° -76° =284°

Reflex \angle AOD=360° -\angle AOD

=360° \left(\angle AOB+\angle BOC+\angle COD\right)

=360° -(38° +38° +38° )

=360° -114°

=246°

Still have questions? Our expert teachers can help you out

Book a free class nowNumber System (Consolidating the Sense of Numberness)

Numbers in India and International System (With Comparison)

Natural Numbers and Whole Numbers (Including Patterns)

Proportion (Including Word Problems)

Idea of Speed, Distance and Time

Fundamental Concepts (Algebra)

Fundamental Operations (Related to Algebraic Expressions)

Substitution (Including Use of Brackets as Grouping Symbols)

Framing Algebraic Expressions (Including Evaluation)

Simple (Linear) Equations (Including Word Problems)

Fundamental Concepts (Geometry)

Properties of Angles and Lines (Including Parallel Lines)

Triangles (Including Types, Properties and Construction)

Revision Exercise on Symmetry (Including Constructions on Symmetry)

Perimeter and Area of Plane Figures

Q13)

In the given figure :

(i) If ∠AOB = 45°, ∠BOC = 30° and ∠AOD= 110°;

find : angles COD and BOD.

(ii) If ∠BOC = ∠DOC = 34° and ∠AOD = 120° ;

find : angle AOB and angle AOC.

(iii) If ∠AOB = ∠BOC = ∠COD = 38°

find : reflex angle AOC and reflex angle AOD.

Solution 13:

(i) \angle COD=\angle AOD-\angle AOC

=\angle AOD-\left(\angle AOB+\angle BOC\right)

=110° -(45° +30°)

=110°-75°=35°

\angle BOD=\angle AOD-\angle AOB

=110°-45°

=65°

(ii) \angle AOB=\angle AOD-\angle BOD

=\angle AOD-\left(\angle BOC+\angle COD\right)

=120° - (34°+34°)

=120° -68°

=86°

(iii) Reflex \angle AOC=360° - \angle AOC

=360° - \left(\angle BOC+\angle COD\right)

=360° -(38° +38°)

=360° -76° =284°

Reflex \angle AOD=360° -\angle AOD

=360° \left(\angle AOB+\angle BOC+\angle COD\right)

=360° -(38° +38° +38° )

=360° -114°

=246°

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