Selina solutions

Selina solutions

Grade 6

Simple (Linear) Equations (Including Word Problems) | Exercise 22(C)

Question 10

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Question 10

Q10) \frac{z}{6}=-1\frac{2}{3}

Solution 10:

\frac{z}{6}=-1\frac{2}{3}

\frac{z}{6}=-\frac{5}{3}

z=\frac{-5\times6}{3}=-5\times2

z = - 10

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