Selina solutions

Selina solutions

Grade 6

Estimation | Exercise 2(B)

Question 1

Q1) Estimate the sum of each pair of numbers to the nearest ten :

(i) 67 and 44

(ii) 34 and 87

(iii) 23 and 66

(iv) 78 and 18

(v) 96 and 55

(vi) 76 and 62

(vii) 457 and 175

(viii) 474 and 173

(ix) 527 and 267

Solution 1:

(i) 67 and 44

67 to the nearest ten 70 and 44 to the nearest ten = 40

∴ Required sum (70+40) = 110

(ii) 34 and 87

34 to the nearest ten = 30 and 87 to the nearest ten = 90

∴ Required sum = (30+90) = 120

(iii) 23 and 66

23 to the nearest ten = 20 and 66 to the nearest ten = 70

∴ Required sum = (20+70) = 90

(iv) 78 and 18

78 to the nearest ten = 80 and 18 to the nearest ten = 20

∴ Required sum = (80+20) = 100

(v) 96 and 55

76 to the nearest ten = 80 and 62 to the nearest ten = 60

∴ Required sum = (80+60) = 140

(vi) 76 and 62

76 to the nearest ten = 80 and 62 to the nearest ten = 180

∴ Required sum = (80+60) = 140

(vii) 457 and 175

457 to the nearest ten = 460 and 175 to the nearest ten = 180

∴ Required sum = (460+180) = 640

(viii) 474 and 173

474 to the nearest ten = 470 and , 173 to the nearest ten = 170

∴ Required sum = (470+170) = 640

(ix) 527 and 267

527 to the nearest ten = 530 and, 267 to the nearest ten = 270

∴ Required sum = (530+270) = 800

Still have questions? Our expert teachers can help you out

Book a free class now

Want to top your mathematics exam ?

Learn from an expert tutor.

Book a free class now
subject-cta

Question 1

Q1) Estimate the sum of each pair of numbers to the nearest ten :

(i) 67 and 44

(ii) 34 and 87

(iii) 23 and 66

(iv) 78 and 18

(v) 96 and 55

(vi) 76 and 62

(vii) 457 and 175

(viii) 474 and 173

(ix) 527 and 267

Solution 1:

(i) 67 and 44

67 to the nearest ten 70 and 44 to the nearest ten = 40

∴ Required sum (70+40) = 110

(ii) 34 and 87

34 to the nearest ten = 30 and 87 to the nearest ten = 90

∴ Required sum = (30+90) = 120

(iii) 23 and 66

23 to the nearest ten = 20 and 66 to the nearest ten = 70

∴ Required sum = (20+70) = 90

(iv) 78 and 18

78 to the nearest ten = 80 and 18 to the nearest ten = 20

∴ Required sum = (80+20) = 100

(v) 96 and 55

76 to the nearest ten = 80 and 62 to the nearest ten = 60

∴ Required sum = (80+60) = 140

(vi) 76 and 62

76 to the nearest ten = 80 and 62 to the nearest ten = 180

∴ Required sum = (80+60) = 140

(vii) 457 and 175

457 to the nearest ten = 460 and 175 to the nearest ten = 180

∴ Required sum = (460+180) = 640

(viii) 474 and 173

474 to the nearest ten = 470 and , 173 to the nearest ten = 170

∴ Required sum = (470+170) = 640

(ix) 527 and 267

527 to the nearest ten = 530 and, 267 to the nearest ten = 270

∴ Required sum = (530+270) = 800

Still have questions? Our expert teachers can help you out

Book a free class now

Want to top your mathematics exam ?

Learn from an expert tutor.

Book a free class now
subject-cta
linkedin instgram facebook youtube
2020 © Quality Tutorials Pvt Ltd All rights reserved
linkedin instgram facebook youtube