Selina solutions

Selina solutions

Grade 6

Idea of Speed, Distance and Time | Exercise 17(A)

Question 1

Q1) A train covers 51 km in 3 hours. Calculate its speed. How far does the train go in 30 minutes?

Solution 1:

Given: Distance= 51 km

Time= 3 hours

Therefore Speed = \frac{Dis\tan ce}{Time}

= \frac{51}{3}

=17km/h

Now,

Time= 30 minutes = \frac{30}{60}h=\frac{1}{2}h

Speed=17km/hr

Distance travelled = Speed\times Time

=17\times\frac{1}{2}=8.5\ km

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subject-cta

Question 1

Q1) A train covers 51 km in 3 hours. Calculate its speed. How far does the train go in 30 minutes?

Solution 1:

Given: Distance= 51 km

Time= 3 hours

Therefore Speed = \frac{Dis\tan ce}{Time}

= \frac{51}{3}

=17km/h

Now,

Time= 30 minutes = \frac{30}{60}h=\frac{1}{2}h

Speed=17km/hr

Distance travelled = Speed\times Time

=17\times\frac{1}{2}=8.5\ km

Still have questions? Our expert teachers can help you out

Book a free class now

Want to top your mathematics exam ?

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subject-cta
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