Selina solutions

Selina solutions

Grade 6

Ratio | Exercise 11(C)

Question 10

Q10) Mr. Gupta divides Rs 81000 among his three children Ashok, Mohit and Geeta in such a way that Ashok gets four times what Mohit gets and Mohit gets 2.5 times what Geeta gets. Find the share of each of them.

Solution:

Let the share of Geeta = 1

Share of Mohit is (2-5 times of Geeta) = 2:5

Share of Ashok is (4 times of Mohit) = 4 x 2.5 = 10

Ratio = 1:2.5 :10 = 1 x 2.5 x 2 : 10 x 2 = 2.5 : 20

Sum of ratio = 2 + 5 + 20 = 27

Share of Geeta = \frac{2}{27}\times81000=2\times3000=Rs.6000

Share of Mohit = \frac{5}{27}\times81000=5\times3000=Rs.15000

Share of Ashok = \frac{20}{27}\times81000=20\times3000=Rs.60000

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Question 10

Q10) Mr. Gupta divides Rs 81000 among his three children Ashok, Mohit and Geeta in such a way that Ashok gets four times what Mohit gets and Mohit gets 2.5 times what Geeta gets. Find the share of each of them.

Solution:

Let the share of Geeta = 1

Share of Mohit is (2-5 times of Geeta) = 2:5

Share of Ashok is (4 times of Mohit) = 4 x 2.5 = 10

Ratio = 1:2.5 :10 = 1 x 2.5 x 2 : 10 x 2 = 2.5 : 20

Sum of ratio = 2 + 5 + 20 = 27

Share of Geeta = \frac{2}{27}\times81000=2\times3000=Rs.6000

Share of Mohit = \frac{5}{27}\times81000=5\times3000=Rs.15000

Share of Ashok = \frac{20}{27}\times81000=20\times3000=Rs.60000

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