  Selina solutions

Q11) Ratio of distance of the school from A’s home to the distance of the school from B’s home is 2 : 1.

(i) Who lives nearer to the school?

(ii) Complete the following table :

Solution:

Ratio of distance of the school from A’s home to the

Distance of the school from B’s hence = 2:1

(i) B lives nearest to the school

(ii) Let A’s home is 2x km from school and B’s home is x km

Distance of school from A’s home = 2 x Distance of school from B’s home

> If A lives at a distance of 4km, then B lives at a distance of = \frac{1}{2}\times4=2km

> If B lives at a distance of 9km, then A lives at a distance of = 2 x 9 = 18 km

> If A lives at a distance of 8km, then B lives at a distance of = \frac{1}{2}\times8=4km

> If B lives at a distance of 8km, then A lives at a distance of = 2 x 8 = 16 km

> If A lives at a distance of 6km, then B lives at a distance of = \frac{1}{2}\times6=3km

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