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RS Aggarwal Solutions Class 9 Mathematics Solutions for Factorization of Polynomials Exercise 3F in Chapter 3 - Factorization of Polynomials

Question 9 Factorization of Polynomials Exercise 3F

1 − 27𝑎^3

Answer:

1 − 27𝑎^3

According to the equation,

𝑎^3 − 𝑏^3 = (𝑎 − 𝑏)(𝑎^2 + 𝑎𝑏 + 𝑏^2)

So we get,

1 − 27𝑎^3

= 1^3 − (3𝑎)^3

Using the formula,

= (1 − 3𝑎)(1^2 + 3𝑎 + (3𝑎)^2)

= (1 − 3𝑎)( 1^2 + 3𝑎 + 9𝑎^2)

= (1 − 3𝑎)( 1 + 3𝑎 + 9𝑎^2)

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