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RS Aggarwal Solutions Class 9 Mathematics Solutions for Factorization of Polynomials Exercise 3F in Chapter 3 - Factorization of Polynomials
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1 − 27𝑎^3
Answer:
1 − 27𝑎^3
According to the equation,
𝑎^3 − 𝑏^3 = (𝑎 − 𝑏)(𝑎^2 + 𝑎𝑏 + 𝑏^2)
So we get,
1 − 27𝑎^3
= 1^3 − (3𝑎)^3
Using the formula,
= (1 − 3𝑎)(1^2 + 3𝑎 + (3𝑎)^2)
= (1 − 3𝑎)( 1^2 + 3𝑎 + 9𝑎^2)
= (1 − 3𝑎)( 1 + 3𝑎 + 9𝑎^2)
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