RS Aggarwal Solutions Class 9 Mathematics Solutions for Factorization of Polynomials Exercise 3F in Chapter 3 - Factorization of Polynomials

Question 7 Factorization of Polynomials Exercise 3F

𝑥^5 + 𝑥^2


𝑥^5 + 𝑥^2

We can write the given question as,

𝑥^5 + 𝑥^2 = 𝑥^2(𝑥^3 + 1)

According to the equation,

𝑎^3 + 𝑏^3 = (𝑎 + 𝑏)(𝑎^2 − 𝑎𝑏 + 𝑏^2)

So we get,

𝑥^2(𝑥^3 + 1)

= 𝑥^2(𝑥^3 + 1^3)

Based on the equation,

= 𝑥^2[(𝑥 + 1)(𝑥^2 − 𝑥 + 1^2)]

= 𝑥^2(𝑥 + 1)(𝑥^2 − 𝑥 + 1^2)

Video transcript
"hi students welcome to lido i hope your studies are going well you are watching all videos solving all question the question we have for the day is x cube plus x to the power 2 so let's get started now to solve the question first we will take x square as a common so from first part x cube is left from second part 1 is left now here we will apply the formula which is a cube plus b q 1 can be written as 1 cube it will be same as it is so the formula will be a plus b a square plus sorry minus a b plus b square this we will use over here so now this x square will remain as it is the bracket will get changed in x plus 1 in the second bracket x x square minus x multiplied by 1 plus 1 square now if you further simplify this x square will be as it is in the square brack in the curl bracket x plus 1 then x square then minus x plus 1 and square bracket close now we are not going to simplify any more because this will further make a question go back to the previous question so that's why we will consider this as a our answer so let's highlight this so that we can clearly see this is our answer for the question i hope you understood the question for any doubt you can write in the comment section for regular updates do subscribe to the leader channel thank you "
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