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7𝑎^3 + 56𝑏^3

Answer:

7𝑎^3 + 56𝑏^3

We can write the given question as,

7𝑎^3 + 56𝑏^3 = 7(𝑎^3 + 8𝑏^3)

According to the equation,

𝑎^3 + 𝑏^3 = (𝑎 + 𝑏)(𝑎^2 − 𝑎𝑏 + 𝑏^2)

So we get,

7(𝑎^3 + 8𝑏^3)

= 7[(𝑎)^3 + (2𝑏)^3]

Using the formula

= 7[(𝑎 + 2𝑏)(𝑎^2 − 𝑎(2𝑏) + (2𝑏)^2]

= 7(𝑎 + 2𝑏)( 𝑎^2 − 2𝑎𝑏 + 4𝑏^2)

"hi students
welcome to leo learning
i hope you are watching all videos
so you have solved many more questions
before this
and you have understood as well so today
we have one of the question in the
series
so the question we have is 7
a cube plus 56 bq
now to solve the question first we will
take 7 as a common
so it will be a cube plus 8 b
cube now 7
a cube plus 8 can be written as 2
and b whole cube
now here we'll apply the formula which
is equals
a q plus b cube is equals to
a plus b multiplied by a square minus
twice
minus a b plus
b square
so 7 will remain as it is it is a
in bracket a plus 2 b
in for the bracket it's a
square minus 2
a b plus 2
b whole square
now 7 it's
in the first bracket will be as it is 7
a plus b
in the second bracket a square minus
twice a b
plus 4 b
square
so this way
we can simplify this now we'll not
simplify anymore after this
because doing a multiplication will
further
go back to the same question so now this
will be
our final answer
so i hope you understood the question
we just used one formula aq plus bq
for any doubt you can write in the
comment section for regular updates do
subscribe to the video channel
thank you
"

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