73 563 We can write the given question as 73 563 73 83 According to the equation 3 3 2 2 So we get 73 83 73 23 Using the formula 7 22 2 22 7 2 2 2 42

RS Aggarwal Solutions Class 9 Mathematics Solutions for Factorization of Polynomials Exercise 3F in Chapter 3 - Factorization of Polynomials

Question 6 Factorization of Polynomials Exercise 3F

7𝑎^3 + 56𝑏^3

Answer:

7𝑎^3 + 56𝑏^3

We can write the given question as,

7𝑎^3 + 56𝑏^3 = 7(𝑎^3 + 8𝑏^3)

According to the equation,

𝑎^3 + 𝑏^3 = (𝑎 + 𝑏)(𝑎^2 − 𝑎𝑏 + 𝑏^2)

So we get,

7(𝑎^3 + 8𝑏^3)

= 7[(𝑎)^3 + (2𝑏)^3]

Using the formula

= 7[(𝑎 + 2𝑏)(𝑎^2 − 𝑎(2𝑏) + (2𝑏)^2]

= 7(𝑎 + 2𝑏)( 𝑎^2 − 2𝑎𝑏 + 4𝑏^2)

Video transcript

"hi students welcome to leo learning i hope you are watching all videos so you have solved many more questions before this and you have understood as well so today we have one of the question in the series so the question we have is 7 a cube plus 56 bq now to solve the question first we will take 7 as a common so it will be a cube plus 8 b cube now 7 a cube plus 8 can be written as 2 and b whole cube now here we'll apply the formula which is equals a q plus b cube is equals to a plus b multiplied by a square minus twice minus a b plus b square so 7 will remain as it is it is a in bracket a plus 2 b in for the bracket it's a square minus 2 a b plus 2 b whole square now 7 it's in the first bracket will be as it is 7 a plus b in the second bracket a square minus twice a b plus 4 b square so this way we can simplify this now we'll not simplify anymore after this because doing a multiplication will further go back to the same question so now this will be our final answer so i hope you understood the question we just used one formula aq plus bq for any doubt you can write in the comment section for regular updates do subscribe to the video channel thank you "

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