𝑥^3 − 3𝑥^2 + 3𝑥 + 7
𝑥^3 − 3𝑥^2 + 3𝑥 + 7
We can write the given question as
= 𝑥^3 − 3𝑥^2 + 3𝑥 − 1 + 8
By grouping the terms
= (𝑥^3 − 3𝑥^2 + 3𝑥 − 1) + 8
We know that (𝑎 − 𝑏)^3 = 𝑎^3 − 3𝑎^2𝑏 + 3𝑎𝑏^2 − 𝑏^3
So we get,
= (𝑥 − 1)^3 + 2^3
According to the equation
𝑎^3 + 𝑏^3 = (𝑎 + 𝑏)(𝑎^2 − 𝑎𝑏 + 𝑏^2)
We get,
= ((𝑥 − 1) + 2)((𝑥 − 1)^2 − 2(𝑥 − 1) + 2^2)
According to the equation
(𝑎 − 𝑏)^2 = 𝑎^2 − 2𝑎𝑏 + 𝑏^2
= (𝑥 − 1 + 2)( 𝑥^2 − 2𝑥(1) + 1^2 − 2𝑥 + 2 + 4)
On further simplification
= (𝑥 + 1)( 𝑥^2 − 2𝑥 + 1 − 2𝑥 + 6)
= (𝑥 + 1)( 𝑥^2 − 4𝑥 + 7)
Lido
Courses
Quick Links
Terms & Policies
Terms & Policies