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1029 − 3𝑥^3

Answer:

1029 − 3𝑥^3

We can write the given question as,

1029 − 3𝑥^3 = 3(343 − 𝑥^3)

According to the equation,

𝑎^3 − 𝑏^3 = (𝑎 − 𝑏)(𝑎^2 + 𝑎𝑏 + 𝑏^2)

So we get,

3(343 − 𝑥^3)

= 3[7^3 − 𝑥^3]

Based on the formula,

= 3[(7 − 𝑥)(7^2 + 7𝑥 + 𝑥^2)]

= 3(7 − 𝑥)(49 + 7𝑥 + 𝑥^2)

"hello guys welcome back to your homework
i'm ravanth kumar working as a tutor at
leader
so today we are going to solve one very
interesting question and it's really
very easy
so how we can do it so let's see here
1029
minus 3 x cube so this is the question i
have given here
so this is 1 0 2 9
and 3 x cube are not the perfect cubes
so we need to take some common here
so that is if you are taking 3 as common
here it will be remaining with 343
minus x cube right so now 343 and x cube
are the perfect cubes
so now 343 can be written in the form of
x whole cube
minus x whole cube right so your three
will be the
outside then it is in the format of a
cube
minus b cube so that is equals to a
minus b
of a square plus a b plus b
square right so that is equals to here
uh just substitute each and everything
values here a and b
so that is 7 minus x of 7
minus x of 7 squared plus
a b that is 7x plus and your b square
that is x
square so that will be resulting of 3 of
7 minus
x so whole of that is
7 square means 49 plus 7x plus
x square so that is only written here so
i hope it is everything clear to
everyone
if you have any doubts please comment
below don't forget to subscribe to this
channel
thank you so much for watching this stay
tuned thank you
"

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