Factorization of Polynomials | Factorization of Polynomials Exercise 3F

Question

8𝑥^3 −1/27𝑦^3

Solution
Transcript

"hello guys welcome back to the homework i'm ravind kumar working as a tutor at leader so today we are going to solve and explore one more very easy and interesting question so let's see and now we can solve it okay so that is they have given here it has 8 x cube minus 1 by 27 y cube so that it can be written in the format of 2 x whole cube minus 1 by 3 y whole cube also right so that is equals to again in the format of a minus a cube minus b cube so that is a minus b of a square plus a b plus b squared so that is the thing here so we can solve it 2 x minus 1 by 3 y off so that is a square so that is of 4 x squared plus and here a b right 2 x multiplied by 1 by 3 y plus 1 by 9 y squared so that you will be getting the final answer is 2 x minus 1 by 3 by off of 4 x square plus here you will be getting 2 x by 3 2 x by 3 y plus one by nine y square so that is the thing here so i hope you understand what i've done and video if you have any doubts please comment below don't forget to subscribe to this channel thank you so much for watching this stay tuned thank you "

Accepted Answer

8𝑥^3 −1/27𝑦^3

According to the equation,

𝑎^3 − 𝑏^3 = (𝑎 − 𝑏)(𝑎^2 + 𝑎𝑏 + 𝑏^2)

So we get,

8𝑥^3 −1/27𝑦^3

= (2𝑥)^3 − (1/3𝑦)^3

Based on the formula,

= (2𝑥 −1/3𝑦)((2𝑥)^2 + (2𝑥)(1/3𝑦) + (1/3𝑦)^2)

= (2𝑥 −1/3𝑦)(4𝑥^2 +2𝑥/3𝑦+1/9𝑦^2)

Factorization of Polynomials | Factorization of Polynomials Exercise 3F

Chapters in Secondary school Mathematics class 9 Rs Aggarwal

Exercises in Factorization of Polynomials

Question 13