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RS Aggarwal Solutions Class 9 Mathematics Solutions for Factorization of Polynomials Exercise 3C in Chapter 3 - Factorization of Polynomials

Question 63 Factorization of Polynomials Exercise 3C

6(2𝑥 −3/𝑥)^2 + 7 (2𝑥 −3/𝑥) − 20

Answer:

6(2𝑥 −3/𝑥)^2 + 7 (2𝑥 −3/𝑥) − 20

Consider,

2𝑥 −3/𝑥= a

So we get,

= 6𝑎^2 + 7𝑎 − 20

We can further write it as

= 6𝑎^2 + 15𝑎 − 8𝑎 − 20

By taking the common terms out

= 3a (2a + 5) – 4 (2a + 5)

= (3a – 4) (2a + 5)

Let us replace a by 2𝑥 −3/𝑥

So we get,

(3(2𝑥 −3/𝑥) – 4) (2(2𝑥 −3/𝑥) + 5)

= (6x -9/𝑥– 4) (4x -6/𝑥+ 5)

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