6(2𝑥 −3/𝑥)^2 + 7 (2𝑥 −3/𝑥) − 20
6(2𝑥 −3/𝑥)^2 + 7 (2𝑥 −3/𝑥) − 20
Consider,
2𝑥 −3/𝑥= a
So we get,
= 6𝑎^2 + 7𝑎 − 20
We can further write it as
= 6𝑎^2 + 15𝑎 − 8𝑎 − 20
By taking the common terms out
= 3a (2a + 5) – 4 (2a + 5)
= (3a – 4) (2a + 5)
Let us replace a by 2𝑥 −3/𝑥
So we get,
(3(2𝑥 −3/𝑥) – 4) (2(2𝑥 −3/𝑥) + 5)
= (6x -9/𝑥– 4) (4x -6/𝑥+ 5)
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