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RS Aggarwal Solutions Class 9 Mathematics Solutions for Factorization of Polynomials Exercise 3C in Chapter 3 - Factorization of Polynomials

Question 60 Factorization of Polynomials Exercise 3C

9(2𝑎 − 𝑏)^2 − 4(2𝑎 − 𝑏) − 13

Answer:

9(2𝑎 − 𝑏)^2 − 4(2𝑎 − 𝑏) − 13

Let us consider 2a – b = c

So we get,

= 9𝑐^2 − 4𝑐 − 13

We can further write it as

= 9𝑐^2 − 13𝑐 + 9𝑐 − 13

By taking out the common terms

= c (9c – 13) + 1 (9c – 13)

= (c + 1) (9c – 13)

Let us replace c by 2a – b

So we get,

9(2𝑎 − 𝑏)^2 − 4(2𝑎 − 𝑏) − 13

Then,

= ((2a – b) + 1) (9(2a – b) – 13)

= (2a – b + 1) (18a – 9b – 13)

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