RS Aggarwal Solutions Class 9 Mathematics Solutions for Factorization of Polynomials Exercise 3C in Chapter 3 - Factorization of Polynomials

Question 6 Factorization of Polynomials Exercise 3C

𝑥^2 + 2√3𝑥 − 24

Answer:

The middle term of a quadratic equation must be rewritten as the sum or difference of the two terms, which is known as "splitting the middle term." In terms of the sum or difference of terms, we need to divide the middle term into two halves.

𝑥² + 2√3𝑥 − 24

We can further write it as

= 𝑥² + 4√3𝑥 − 2√3𝑥 − 24

By taking out the common terms

= x (x + 4√3) −2√3(x +4√3)

So we get,

= (x - 2√3) (x +4√3)

Related Questions

𝑥^2 + 11𝑥 + 30

𝑥^2 + 18𝑥 + 32

𝑥^2 + 20𝑥 − 69

𝑥^2 + 19𝑥 − 150

𝑥^2 + 7𝑥 − 98

𝑥^2 − 21𝑥 + 90

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Exercises

Factorization of Polynomials Exercise 3A

Factorization of Polynomials Exercise 3B

Factorization of Polynomials Exercise 3C

Factorization of Polynomials Exercise 3D

Factorization of Polynomials Exercise 3E

Factorization of Polynomials Exercise 3F

Factorization of Polynomials Exercise 3G

Chapters

Number Systems

Polynomials

Factorization of Polynomials

Linear Equations In Two Variables

Coordinate Geometry

Introduction To Euclids Geometry

Lines And Angles

Triangles

Congruence Of Triangles And Inequalities In A Triangle

Quadrilaterals

Areas Of Parallelograms And Triangles

Circles

Geometrical Constructions

Areas Of Triangles And Quadrilaterals

Volume And Surface Area Of Solids

Mean Median And Mode Of Ungrouped Data

Probability