𝑥^2 − 2𝑥 + 7/16
𝑥^2 − 2𝑥 + 7/16
We can further write it as
= 1/16(16𝑥^2 − 32𝑥 + 7)
= 1/16(16𝑥^2 − 4𝑥 − 28𝑥 + 7)
By taking out the common terms
= 1/16[4𝑥 (4𝑥 − 1) − 7(4𝑥 − 1)]
So we get,
=1/16(4𝑥 − 7)(4𝑥 − 1)
= (4x – 1) ( 𝑥/4−7/16)
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