2 26 133 We can further write it as 2 19 7 133 By taking out the common terms x x 19 7 x 19 So we get x 7 x 19

RS Aggarwal Solutions Class 9 Mathematics Solutions for Factorization of Polynomials Exercise 3C in Chapter 3 - Factorization of Polynomials

Question 21 Factorization of Polynomials Exercise 3C

𝑥^2 − 26𝑥 + 133

Answer:

𝑥^2 − 26𝑥 + 133

We can further write it as

= 𝑥^2 − 19𝑥 − 7𝑥 + 133

By taking out the common terms

= x (x – 19) – 7 (x – 19)

So we get,

= (x – 7) (x – 19)

Related Questions

Was This helpful?

Exercises

Factorization of Polynomials Exercise 3A

Factorization of Polynomials Exercise 3B

Factorization of Polynomials Exercise 3C

Factorization of Polynomials Exercise 3D

Factorization of Polynomials Exercise 3E

Factorization of Polynomials Exercise 3F

Factorization of Polynomials Exercise 3G

Chapters

Number Systems

Polynomials

Factorization of Polynomials

Linear Equations In Two Variables

Coordinate Geometry

Introduction To Euclids Geometry

Lines And Angles

Triangles

Quadrilaterals

Areas Of Parallelograms And Triangles

Circles

Geometrical Constructions

Areas Of Triangles And Quadrilaterals

Volume And Surface Area Of Solids

Mean Median And Mode Of Ungrouped Data

Probability