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Rs aggarwal solutions
Grade 9 
Mathematics
Secondary school Mathematics class 9 Rs Aggarwal
Factorization of Polynomials
Factorization of Polynomials Exercise 3B
Question 37
Mathematics
Secondary school Mathematics class 9 Rs Aggarwal
Factorization of Polynomials
Factorization of Polynomials Exercise 3B
Question 37
Factorization of Polynomials | Factorization of Polynomials Exercise 3B
Question 37
CHAPTERS
3. Factorization of Polynomials
4. Linear Equations In Two Variables
6. Introduction To Euclids Geometry
9. Congruence Of Triangles And Inequalities In A Triangle
11. Areas Of Parallelograms And Triangles
14. Areas Of Triangles And Quadrilaterals
15. Volume And Surface Area Of Solids
16𝑥^4 − 1
16𝑥^4 − 1
We can further write it as
= (4𝑥^2)^2 − 1^2
Based on the equation 𝑎^2 − 𝑏^2 = (𝑎 + 𝑏)(𝑎 − 𝑏)
We get,
= (4𝑥^2 + 1)(4𝑥^2 − 1)
On further simplification using the formula
= (4𝑥^2 + 1)( (2𝑥)^2 − 1^2)
So we get,
= (4𝑥^2 + 1)(2𝑥 + 1)(2𝑥 − 1)
Question 37
16𝑥^4 − 1
16𝑥^4 − 1
We can further write it as
= (4𝑥^2)^2 − 1^2
Based on the equation 𝑎^2 − 𝑏^2 = (𝑎 + 𝑏)(𝑎 − 𝑏)
We get,
= (4𝑥^2 + 1)(4𝑥^2 − 1)
On further simplification using the formula
= (4𝑥^2 + 1)( (2𝑥)^2 − 1^2)
So we get,
= (4𝑥^2 + 1)(2𝑥 + 1)(2𝑥 − 1)
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