92 3 8 642 We can further write it as 92 642 3 8 So we get 32 82 3 8 Based on the equation 2 2 We get 3a 8b 3a 8b 3 8 Taking 3a 8b as common 3a 8b 3a 8b 1

RS Aggarwal Solutions Class 9 Mathematics Solutions for Factorization of Polynomials Exercise 3B in Chapter 3 - Factorization of Polynomials

Question 32 Factorization of Polynomials Exercise 3B

9𝑎^2 + 3𝑎 − 8𝑏 − 64𝑏^2

Answer:

9𝑎^2 + 3𝑎 − 8𝑏 − 64𝑏^2

We can further write it as

= 9𝑎^2 − 64𝑏^2 + 3𝑎 − 8𝑏

So we get

= (3𝑎)^2 − (8𝑏)^2 + (3𝑎 − 8𝑏)

Based on the equation 𝑎^2 − 𝑏^2 = (𝑎 + 𝑏)(𝑎 − 𝑏)

We get,

= (3a + 8b) (3a – 8b) +(3𝑎 − 8𝑏)

Taking (3a – 8b) as common

= (3a – 8b) (3a + 8b + 1)

Related Questions

𝟗𝒙^𝟐 − 𝟏𝟔𝒚^𝟐

(𝟐𝟓/𝟒𝒙^𝟐 −𝟏/𝟗𝒚^𝟐)

𝟖𝟏 − 𝟏𝟔𝒙^𝟐

𝟑𝒂^𝟑𝒃 − 𝟐𝟒𝟑𝒂𝒃^𝟑

𝟑𝒙^𝟑 − 𝟒𝟖𝒙

𝟐𝟕𝒂^𝟐 − 𝟒𝟖𝒃^𝟐

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Exercises

Factorization of Polynomials Exercise 3A

Factorization of Polynomials Exercise 3B

Factorization of Polynomials Exercise 3C

Factorization of Polynomials Exercise 3D

Factorization of Polynomials Exercise 3E

Factorization of Polynomials Exercise 3F

Factorization of Polynomials Exercise 3G

Chapters

Number Systems

Polynomials

Factorization of Polynomials

Linear Equations In Two Variables

Coordinate Geometry

Introduction To Euclids Geometry

Lines And Angles

Triangles

Congruence Of Triangles And Inequalities In A Triangle

Quadrilaterals

Areas Of Parallelograms And Triangles

Circles

Geometrical Constructions

Areas Of Triangles And Quadrilaterals

Volume And Surface Area Of Solids

Mean Median And Mode Of Ungrouped Data

Probability