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RS Aggarwal Solutions Class 9 Mathematics Solutions for Factorization of Polynomials Exercise 3B in Chapter 3 - Factorization of Polynomials

Question 30 Factorization of Polynomials Exercise 3B

𝑥^2 − 𝑦^2 + 6𝑦 − 9

Answer:

𝑥^2 − 𝑦^2 + 6𝑦 − 9

We can further write it as

= 𝑥^2 − (𝑦^2 − 6𝑦 + 9)

So we get

= 𝑥^2 − (𝑦^2 − 2 × 𝑦 × 3 + 3^2)

= 𝑥^2 − (𝑦 − 3)^2

Based on the equation 𝑎^2 − 𝑏^2 = (𝑎 + 𝑏)(𝑎 − 𝑏)

We get,

= [x + (y – 3)][x – (y – 3)]

= (x + y – 3) (x – y + 3)

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