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RS Aggarwal Solutions Class 9 Mathematics Solutions for Factorization of Polynomials Exercise 3B in Chapter 3 - Factorization of Polynomials

Question 25 Factorization of Polynomials Exercise 3B

𝑎^2 − 𝑏^2 − 4𝑎𝑐 + 4𝑐^2

Answer:

𝑎^2 − 𝑏^2 − 4𝑎𝑐 + 4𝑐^2

We can write it as

= 𝑎^2 − 4𝑎𝑐 + 4𝑐^2 − 𝑏^2

So we get

= 𝑎^2 − 2 × 𝑎 × 2𝑐 + 2𝑐^2 − 𝑏^2

= (𝑎 − 2𝑐)^2 − 𝑏^2

Based on the equation 𝑎^2 − 𝑏^2 = (𝑎 + 𝑏)(𝑎 − 𝑏)

We get,

= (a – 2c + b) (a – 2c – b)

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