𝒂^𝟑𝒃 − 𝒂^𝟐𝒃 + 5ab – 5b
𝑎^3𝑏 − 𝑎^2𝑏 + 5ab – 5b
By taking 𝑎^2𝑏 common in the first term and 5b as common in the second term
= 𝑎^2𝑏(𝑎 − 1) + 5𝑏(𝑎 − 1)
So we get,
= (a – 1) (𝑎^2𝑏 + 5b)
By taking b as common
= (a – 1) b (𝑎^2 + 5)
So we get,
= b (a – 1) (𝑎^2 + 5)
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