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Three coins are tossed 200 times and we get Three heads: 39 times; two heads: 58 times;

One head: 67 times; o head: 36 times.

When three coins are tossed at random, what is the probability of getting

(i) 3 heads?

(ii) 1 head?

(iii) 0 head?

(iv) 2 heads?

Answer:

It is given that

Number of trials = 200

Number of times 3 heads = 39

Number of times 2 heads = 58

Number of times 1 head = 67

Number of times 0 head = 36

Consider E1, E2, E3 and E4 as the events

(i) So we get

P (E1) = number of times 3 head/ number of trials

By substituting the values

P (E1) = 39/ 200

We get

P (E1) = 0.195

(ii) So we get

P (E2) = number of times 1 head/ number of trials

By substituting the values

P (E2) = 67/ 200

We get

P (E2) = 0.335

(iii) So we get

P (E3) = number of times 0 head/ number of trials

By substituting the values

P (E3) = 36/ 200

We get

P (E3) = 0.18

(iv) So we get

P (E4) = number of times 2 head/ number of trials

By substituting the values

P (E4) = 58/ 200

We get

P (E4) = 0.29

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