Three coins are tossed 200 times and we get Three heads: 39 times; two heads: 58 times;
One head: 67 times; o head: 36 times.
When three coins are tossed at random, what is the probability of getting
(i) 3 heads?
(ii) 1 head?
(iii) 0 head?
(iv) 2 heads?
It is given that
Number of trials = 200
Number of times 3 heads = 39
Number of times 2 heads = 58
Number of times 1 head = 67
Number of times 0 head = 36
Consider E1, E2, E3 and E4 as the events
(i) So we get
P (E1) = number of times 3 head/ number of trials
By substituting the values
P (E1) = 39/ 200
We get
P (E1) = 0.195
(ii) So we get
P (E2) = number of times 1 head/ number of trials
By substituting the values
P (E2) = 67/ 200
We get
P (E2) = 0.335
(iii) So we get
P (E3) = number of times 0 head/ number of trials
By substituting the values
P (E3) = 36/ 200
We get
P (E3) = 0.18
(iv) So we get
P (E4) = number of times 2 head/ number of trials
By substituting the values
P (E4) = 58/ 200
We get
P (E4) = 0.29
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