Two coins are tossed 400 times and we get Two heads: 112 times; one head: 160 times; 0 head: 128 times.
When two coins are tossed at random, what is the probability of getting
(i) 2 heads?
(ii) 1 head?
(iii) 0 head?
It is given that
Number of trials = 400
Number of times 2 head = 112
Number of times 1 head = 160
Number of times 0 head = 128
Take E1, E2 and E3 as the events
(i) So we get
P (E1) = number of times 2 head/ number of trials
By substituting the values
P (E1) = 112/ 400
We get
P (E1) = 0.28
(ii) So we get
P (E2) = number of times 1 head/ number of trials
By substituting the values
P (E2) = 160/ 400
We get
P (E2) = 0.4
(iii) So we get
P (E3) = number of times 0 head/ number of trials
By substituting the values
P (E3) = 128/ 400
We get
P (E3) = 0.32
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