The ages (in years) of 10 teachers in a school are
32, 44, 53, 47, 37, 54, 34, 36, 40, 50.
Find the median age.
By arranging the numbers in ascending order
We get
32, 34, 36, 37, 4, 44, 47, 50, 53, 54
We know that n = 10 which is even
So we get
Median = ½ {(n/2)th term + (n/2 + 1)th term}
It can be written as
Median = ½ {5th term + 6th term)
By substituting the values
Median = ½ (40 + 44)
On further calculation
Median = ½ (84)
We get
Median = 42
Therefore, the median age is 42 years.
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