 # RS Aggarwal Solutions Class 9 Mathematics Solutions for Mean Median And Mode Of Ungrouped Data Exercise 18B in Chapter 18 - Mean Median And Mode Of Ungrouped Data

Question 8 Mean Median And Mode Of Ungrouped Data Exercise 18B

If the mean of the following data is 8, find the value of p.

x f
3 6
5 8
7 15
9 p
11 8
13 4

The mean is the average or computed centre value of a group of numbers used to determine the central tendency of the data. The central tendency statistic is a single value that represents the entire set of data or distribution.

x f fi xi
3 6 18
5 8 40
7 15 105
9 p 9p
11 8 88
13 4 52
Σ fi = 41 + p Σ fi xi = 303 + 9p

It is given that

Mean = 8

We know that

Mean = Σ fi xi/ Σ fi

So we get

(303 + 9p)/ (41 + p) = 8

On further calculation

303 + 9p = 8 (41 + p)

So we get

303 + 9p = 328 + 8p

It can be written as

9p – 8p = 328 – 303

We get

p = 25

Therefore, the value of p is 25.

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