Jump to
- Number Systems
- Polynomials
- Factorization of Polynomials
- Linear Equations In Two Variables
- Coordinate Geometry
- Introduction To Euclids Geometry
- Lines And Angles
- Triangles
- Congruence Of Triangles And Inequalities In A Triangle
- Quadrilaterals
- Areas Of Parallelograms And Triangles
- Circles
- Geometrical Constructions
- Areas Of Triangles And Quadrilaterals
- Volume And Surface Area Of Solids
- Mean Median And Mode Of Ungrouped Data
- Probability
RS Aggarwal Solutions Class 9 Mathematics Solutions for Mean Median And Mode Of Ungrouped Data Exercise 18B in Chapter 18 - Mean Median And Mode Of Ungrouped Data
Prev
The measurements (in mm) of the diameters of the heads of 50 screws are given below:
| Diameter (in mm) (xi) | Number of screws (fi) |
|---|---|
| 34 | 5 |
| 37 | 10 |
| 40 | 17 |
| 43 | 12 |
| 46 | 6 |
Calculate the mean diameter of the heads of the screws.
Answer:
| Diameter (in mm) (xi) | Number of screws (fi) | fi xi |
|---|---|---|
| 34 | 5 | 170 |
| 37 | 10 | 370 |
| 40 | 17 | 680 |
| 43 | 12 | 516 |
| 46 | 6 | 276 |
| - | Σ fi = 50 | Σ fi xi = 2012 |
We know that
Mean diameter of the heads of the screws = Σ fi xi/ Σ fi
By substituting the values
Mean diameter of the heads of the screws = 2012/50 = 40.24mm
Therefore, the mean diameter of the heads of the screws is 40.24mm.
Related Questions
Facebook
Whatsapp
Copy Link
Exercises
Chapters
Lido
Courses
Quick Links
Terms & Policies
Terms & Policies
Connect with us on social media!
2022 © Quality Tutorials Pvt Ltd All rights reserved