Find the missing frequencies in the following frequency distribution whose mean is 50.
x | f |
---|---|
10 | 17 |
30 | f1 |
50 | 32 |
70 | f2 |
90 | 19 |
Total | 120 |
x | f | xifi |
---|---|---|
10 | 17 | 170 |
30 | f1 | 30f1 |
50 | 32 | 1600 |
70 | f2 | 70f2 |
90 | 19 | 1710 |
Total | 120 = Σ fi =68 + f1 + f2 | Σ fi xi = 3480 + 30f1 + 70f2 |
We know that
Σ fi =68 + f1 + f2
It can be written as
120 = 68 + f1 + f2
So we get
f1 + f2 = 52
f2 = 52 - f1 ……. (1)
It is given that
Mean = 50
We know that
Mean = Σ fi xi/ Σ fi
So we get
(3480 + 30f1 + 70f2)/ 120 = 50
Substituting equation (1)
3480 + 30f1 + 70(52 - f1) / 120 = 50
On further calculation
(3480 + 30f1 + 3640 – 70f1)/ 120 = 50
So we get
(7120 - 40f1)/ 120 = 50
It can be written as
6000 = 7120 - 40f1
By subtraction
40f1 = 1120
By division
f1 = 28
By substituting it in equation (1)
f2 = 52 – 28 = 24
Therefore, the missing frequencies are 28 and 24.
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