Find the missing frequencies in the following frequency distribution whose mean is 34.
x | f |
---|---|
10 | 4 |
20 | f1 |
30 | 8 |
40 | f2 |
50 | 3 |
6 | 4 |
Total | 35 |
The average of the given numbers is computed by dividing the total number of numbers by the sum of the given numbers.
x | f | xifi |
---|---|---|
10 | 4 | 40 |
20 | f1 | 20f1 |
30 | 8 | 240 |
40 | f2 | 40f2 |
50 | 3 | 150 |
6 | 4 | 24 |
Total | 35 = Σ fi =19 + f1 + f2 | Σ fi xi = 670 + 20f1 + 40f2 |
We know that
Σ fi =19 + f1 + f2
It can be written as
35 = 19 + f1 + f2
So we get
f1 + f2 = 16 …… (1)
It is given that
Mean = 34
We know that
Mean = Σ fi xi/ Σ fi
So we get
(670 + 20f1 + 40f2)/ 35 = 34
On further calculation
(335 + 10f1 + 20f2)/ 35 = 17
So we get
335 + 10f1 + 20f2 = 595
It can be written as
10f1 + 20f2 = 260
Dividing the equation by 10
f1 + 2f2 = 26 …….. (2)
By subtracting equation (1) from (2)
f2 = 10
Substituting in equation (1)
f1 + 10 = 16
So we get
f1 = 6
Therefore, the missing frequencies are 6 and 10.
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