 # RS Aggarwal Solutions Class 9 Mathematics Solutions for Mean Median And Mode Of Ungrouped Data Exercise 18A in Chapter 18 - Mean Median And Mode Of Ungrouped Data

Question 22 Mean Median And Mode Of Ungrouped Data Exercise 18A

The mean of 11 numbers is 42. If the mean of the first 6 numbers is 37 and that of the last 6 numbers is

46, find the 6th number.

It is given that

Mean of 11 numbers = 42

So the total sum = 42 (11) = 462

Mean of first 6 numbers = 37

So the total sum = 37 (6) = 222

Mean of last 6 numbers = 46

So the total sum = 6 (46) = 276

We know that

6th number = total sum of last 6 numbers + total sum of first 6 numbers – total sum of 11 numbers

By substituting the values

6th number = 276 + 222 – 462

So we get

6th number = 498 – 462 = 36

Therefore, the 6th number is 36.

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