Jump to
- Number Systems
- Polynomials
- Factorization of Polynomials
- Linear Equations In Two Variables
- Coordinate Geometry
- Introduction To Euclids Geometry
- Lines And Angles
- Triangles
- Congruence Of Triangles And Inequalities In A Triangle
- Quadrilaterals
- Areas Of Parallelograms And Triangles
- Circles
- Geometrical Constructions
- Areas Of Triangles And Quadrilaterals
- Volume And Surface Area Of Solids
- Mean Median And Mode Of Ungrouped Data
- Probability
RS Aggarwal Solutions Class 9 Mathematics Solutions for Mean Median And Mode Of Ungrouped Data Exercise 18A in Chapter 18 - Mean Median And Mode Of Ungrouped Data
Prev
The mean of 31 results is 60. If the mean of the first 16 results is 58 and that of the last 16 results is 62,
find the 16th result.
Answer:
It is given that
Mean of 31 results = 60
So the total sum = 31 (60) = 1860
We know that
Mean of first 16 results = 58
So the total sum = 16 (58) = 928
Mean of last 16 results = 62
So the total sum = 16 (62) = 992
We get the 16th result = total sum of first 16 results + total sum of last 16 results – total sum of 31 results
By substituting the values
16th result = 928 + 992 – 1860
On further calculation
16th result = 1920 – 1860 = 60
Therefore, the 16th result is 60.
Related Questions
Facebook
Whatsapp
Copy Link
Exercises
Chapters
Lido
Courses
Quick Links
Terms & Policies
Terms & Policies
Connect with us on social media!
2022 © Quality Tutorials Pvt Ltd All rights reserved