# RS Aggarwal Solutions Class 9 Mathematics Solutions for Mean Median And Mode Of Ungrouped Data Exercise 18A in Chapter 18 - Mean Median And Mode Of Ungrouped Data

Question 11 Mean Median And Mode Of Ungrouped Data Exercise 18A

The mean of 12 numbers is 40. If each number is divided by 8, what will be the mean of the new

numbers?

Consider x1, x2, ……. x12 as the given numbers

So we get

Mean = [x1 + x2 + ……. + x12]/12

It is given that mean = 40

(x1 + x2 + ……. + x12)/12 = 40

By cross multiplication

x1 + x2 + ……. + x12 = 480 …… (1)

Take (x1 ÷ 8), (x2 ÷ 8), ……… (x12 ÷ 8) as new numbers

So the mean of new numbers = [(x1 ÷ 8) + (x2 ÷ 8) + ……… + (x12 ÷ 8)]/12

From equation (1) we get

[(x1 ÷ 8) + (x2 ÷ 8) + ……… + (x12 ÷ 8)]/12 = (480 ÷ 8)/12

On further calculation

Mean of new numbers = 60/12 = 5

Therefore, the mean of the new numbers is 5.

Related Questions

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE
Maths
ICSE
Science
CBSE

Science
ICSE
English
CBSE
English
ICSE
Coding

Terms & Policies

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry
Connect with us on social media!