Find the mean of:
(i) the first eight natural numbers
(ii) the first ten odd numbers
(iii) the first seven multiples of 5
(iv) all the factors of 20
(v) all prime numbers between 50 and 80.
(i) We know that
First eight natural numbers = 1, 2, 3, 4, 5, 6, 7 and 8
So we get
Mean = sum of numbers/ total numbers
By substituting the values
Mean = (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8)/8
On further calculation
Mean = 36/8
By division
Mean = 4.5
Therefore, the mean of the first eight natural numbers is 4.5.
(ii) We know that
First ten odd numbers = 1, 3, 5, 7, 9, 11, 13, 15, 17 and 19
So we get
Mean = sum of numbers/ total numbers
By substituting the values
Mean = (1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19)/10
On further calculation
Mean = 100/10
By division
Mean = 10
Therefore, the mean of first ten odd numbers is 10.
(iii) We know that
First seven multiples of five = 5, 10, 15, 20, 25, 30 and 35
So we get
Mean = sum of numbers/ total numbers
By substituting the values
Mean = (5 + 10 + 15 + 20 + 25 + 30 + 35)/7
On further calculation
Mean = 140/7
By division
Mean = 20
Therefore, the mean of first seven multiples of five is 20.
(iv) We know that
All the factors of 20 = 1, 2, 4, 5, 10 and 20
So we get
Mean = sum of numbers/ total numbers
By substituting the values
Mean = (1 + 2 + 4 + 5 + 10 + 20)/6
On further calculation
Mean = 42/6
By division
Mean = 7
Therefore, the mean of all the factors of 20 is 7.
(v) We know that
All prime numbers between 50 and 80 = 53, 59, 61, 67, 71, 73 and 79
So we get
Mean = sum of numbers/ total numbers
By substituting the values
Mean = (53 + 59 + 61 + 67 + 71 + 73 + 79)/7
On further calculation
Mean = 463/7
So we get
Mean = 66*1/7
Therefore, the mean of all prime numbers between 50 and 80 is 66*1/7.
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