A hemispherical bowl made of brass has inner diameter 10.5cm. Find the cost of tin-plating it on the inside at the rate of ₹ 32 per 100cm2.
ANSWER:
It is given that
Inner diameter of the hemispherical bowl = 10.5cm
Inner radius of the hemispherical bowl = 10.5/2 = 5.25cm
We know that
Inner curved surface area of the bowl = 2 πr2
By substituting the values
Inner curved surface area of the bowl = 2 × (22/7) × 5.252
On further calculation
Inner curved surface area of the bowl = 2 × (22/7) × 27.5625
So we get
Inner curved surface area of the bowl = 173.25 cm2
It is given that
Cost of tin plating inside = ₹ 32 per 100cm2
So the cost of tin plating 173.25 cm2 = ₹ (32 × 173.25)/100 = ₹ 55.44
Therefore, the cost of tin plating it on the inside is ₹ 55.44.
Lido
Courses
Quick Links
Terms & Policies
Terms & Policies