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Volume And Surface Area Of Solids | Volume And Surface Area Of Solids Exercise 15D

Question 27

A hemispherical bowl is made of steel 0.25cm thick. The inner radius of the bowl is 5cm. Find the outer curved surface area of the bowl.

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ANSWER:

It is given that

Inner radius of the bowl = 5cm

Thickness of the bowl = 0.25cm

External radius = 5 + 0.25 = 5.25cm

We know that

Outer curved surface area of the bowl = 2 πr2

By substituting the values

Outer curved surface area of the bowl = 2 × (22/7) × 5.252

On further calculation

Outer curved surface area of the bowl = 2 × (22/7) × 27.5625

So we get

Outer curved surface area of the bowl = 173.25 cm2

Therefore, the outer curved surface area of the bowl is 173.25 cm2.

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Our top 5% students will be awarded a special scholarship to Lido.

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Question 27

A hemispherical bowl is made of steel 0.25cm thick. The inner radius of the bowl is 5cm. Find the outer curved surface area of the bowl.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

ANSWER:

It is given that

Inner radius of the bowl = 5cm

Thickness of the bowl = 0.25cm

External radius = 5 + 0.25 = 5.25cm

We know that

Outer curved surface area of the bowl = 2 πr2

By substituting the values

Outer curved surface area of the bowl = 2 × (22/7) × 5.252

On further calculation

Outer curved surface area of the bowl = 2 × (22/7) × 27.5625

So we get

Outer curved surface area of the bowl = 173.25 cm2

Therefore, the outer curved surface area of the bowl is 173.25 cm2.

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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