 # RS Aggarwal Solutions Class 9 Mathematics Solutions for Volume And Surface Area Of Solids Exercise 15D in Chapter 15 - Volume And Surface Area Of Solids

Question 26 Volume And Surface Area Of Solids Exercise 15D

A hemispherical bowl is made of steel 0.5cm thick. The inside radius of the bowl is 4cm. Find the volume of steel used in making the bowl.

A hemisphere is formed when a plane cuts across the sphere at the centre or in equal portions. A hemisphere, we can say, is exactly half of a sphere. A sphere, in general, has exactly two hemispheres.

It is given that

Internal radius of the hemispherical bowl = 4cm

Thickness of the hemispherical bowl = 0.5cm

We know that

External radius = 4 + 0.5 = 4.5 cm

We know that

Volume of steel used in making the hemispherical bowl = volume of the shell

So we get

Volume of steel used in making the hemispherical bowl = 2/3 π (4.53 - 43)

On further calculation

Volume of steel used in making the hemispherical bowl = 2/3 × (22/7) × [91.125 – 64]

We get

Volume of steel used in making the hemispherical bowl = 2/3 × (22/7) × 27.125 = 56.83 cm3

Therefore, the volume of steel used in making the bowl is 56.83 cm3. Related Questions

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE
Maths
ICSE
Science
CBSE

Science
ICSE
English
CBSE
English
ICSE
Coding

Terms & Policies

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry
Connect with us on social media!