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RS Aggarwal Solutions Class 9 Mathematics Solutions for Volume And Surface Area Of Solids Exercise 15D in Chapter 15 - Volume And Surface Area Of Solids

Question 24 Volume And Surface Area Of Solids Exercise 15D

A hemisphere of lead of radius 9cm is cast into a right circular cone of height 72cm. Find the radius of the base of the cone.

Answer:

ANSWER:

It is given that

Radius of hemisphere = 9cm

Height of cone = 72cm

Consider r cm as the radius of the base of cone

We know that

1/3 πr2h = 2/3 πR3

By substituting the values

1/3 × π × r2 × 72 = 2/3 × π × 93

On further calculation

r2 = (2/3 × π × 729)/ (1/3 × π × 72)

So we get

r2 = 20.25

By taking square root

r = 4.5 cm

Therefore, the radius of the base of the cone is 4.5 cm.

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