A hemisphere of lead of radius 9cm is cast into a right circular cone of height 72cm. Find the radius of the base of the cone.
ANSWER:
It is given that
Radius of hemisphere = 9cm
Height of cone = 72cm
Consider r cm as the radius of the base of cone
We know that
1/3 πr2h = 2/3 πR3
By substituting the values
1/3 × π × r2 × 72 = 2/3 × π × 93
On further calculation
r2 = (2/3 × π × 729)/ (1/3 × π × 72)
So we get
r2 = 20.25
By taking square root
r = 4.5 cm
Therefore, the radius of the base of the cone is 4.5 cm.
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