 # RS Aggarwal Solutions Class 9 Mathematics Solutions for Volume And Surface Area Of Solids Exercise 15C in Chapter 15 - Volume And Surface Area Of Solids

Question 12 Volume And Surface Area Of Solids Exercise 15C

A man uses a piece of canvas having an area of 551m2, to make a conical tent of base radius 7m. Assuming that all the stitching margins and wastage incurred while cutting, amount to approximately 1m2, find the volume of the tent that can be made with it.

It is given that

The radius of the conical tent = 7m

So the area of canvas required to make the conical tent = 551 – 1 = 550 m2

We know that

The curved surface area of a conical tent = 550

So we get

Πrl = 550

By substituting the values

(22/7) × 7× l = 550

On further calculation

l = 550/22 = 25m

We know that

Height h = √ (l2 - r2)

By substituting the values

h = √ (252 - 72)

On further calculation

h = √ (625 – 49) = √ 576

So we get

h = 24m

We know that

The volume of the conical tent = 1/3 πr2h

By substituting the values

Volumes of the conical tent = 1/3 × (22/7) × 72 × 24

On further calculation

The volume of the conical tent = 1232 m3

Therefore, the volume of the conical tent is 1232 m3.

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