A man uses a piece of canvas having an area of 551m2, to make a conical tent of base radius 7m. Assuming that all the stitching margins and wastage incurred while cutting, amount to approximately 1m2, find the volume of the tent that can be made with it.
ANSWER:
It is given that
The radius of the conical tent = 7m
So the area of canvas required to make the conical tent = 551 – 1 = 550 m2
We know that
The curved surface area of a conical tent = 550
So we get
Πrl = 550
By substituting the values
(22/7) × 7× l = 550
On further calculation
l = 550/22 = 25m
We know that
Height h = √ (l2 - r2)
By substituting the values
h = √ (252 - 72)
On further calculation
h = √ (625 – 49) = √ 576
So we get
h = 24m
We know that
The volume of the conical tent = 1/3 πr2h
By substituting the values
Volumes of the conical tent = 1/3 × (22/7) × 72 × 24
On further calculation
The volume of the conical tent = 1232 m3
Therefore, the volume of the conical tent is 1232 m3.
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