RS Aggarwal Solutions Class 9 Mathematics Solutions for Volume And Surface Area Of Solids Exercise 15B in Chapter 15 - Volume And Surface Area Of Solids

Question 31 Volume And Surface Area Of Solids Exercise 15B

A cylindrical container with a diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32cm × 22cm × 14cm). Find a rise in the level of water when the solid is completely submerged.

Consider h cm as the rise in the level of water

We know that

Volume of a cylinder of height h and base radius 28cm = volume of rectangular iron solid

By substituting the values

(22/7) × 282 × h = 32 × 22 × 14

On further calculation

22 × 28 × 4 × h = 32 × 22 × 14

So we get

h = (32 × 22 × 14)/ (22 × 28 × 4)

By division

h = 4cm

Therefore, the rise in the level of water when the solid is completely submerged is 4cm.

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