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Volume And Surface Area Of Solids | Volume And Surface Area Of Solids Exercise 15B

Question 31

A cylindrical container with a diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32cm × 22cm × 14cm). Find a rise in the level of water when the solid is completely submerged.

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ANSWER:

Consider h cm as the rise in the level of water

We know that

Volume of a cylinder of height h and base radius 28cm = volume of rectangular iron solid

By substituting the values

(22/7) × 282 × h = 32 × 22 × 14

On further calculation

22 × 28 × 4 × h = 32 × 22 × 14

So we get

h = (32 × 22 × 14)/ (22 × 28 × 4)

By division

h = 4cm

Therefore, the rise in the level of water when the solid is completely submerged is 4cm.

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Our top 5% students will be awarded a special scholarship to Lido.

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Question 31

A cylindrical container with a diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32cm × 22cm × 14cm). Find a rise in the level of water when the solid is completely submerged.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

ANSWER:

Consider h cm as the rise in the level of water

We know that

Volume of a cylinder of height h and base radius 28cm = volume of rectangular iron solid

By substituting the values

(22/7) × 282 × h = 32 × 22 × 14

On further calculation

22 × 28 × 4 × h = 32 × 22 × 14

So we get

h = (32 × 22 × 14)/ (22 × 28 × 4)

By division

h = 4cm

Therefore, the rise in the level of water when the solid is completely submerged is 4cm.

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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