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Rs aggarwal solutions

CHAPTERS

3. Factorization of Polynomials

4. Linear Equations In Two Variables

6. Introduction To Euclids Geometry

9. Congruence Of Triangles And Inequalities In A Triangle

11. Areas Of Parallelograms And Triangles

14. Areas Of Triangles And Quadrilaterals

15. Volume And Surface Area Of Solids

A juice seller has a large cylindrical vessel of base radius 15cm filled up to a height of 32cm with orange juice. The juice is filled in small cylindrical glasses of radius 3cm up to a height of 8cm, and sold for ₹ 15 each. How much money does he receive by selling the juice completely?

ANSWER:

The dimensions of the cylindrical vessel

Radius = 15cm

Height = 32cm

We know that

Volume of cylindrical vessel = πr2h

By substituting the values

Volume of cylindrical vessel = (22/7) × (15)2 × 32

So we get

Volume of cylindrical vessel = 22628.571 cm3

The dimensions of cylindrical glass are

Radius = 3cm

Height = 8cm

We know that

Volume of each small cylindrical glass = πr2h

By substituting the values

Volume of each small cylindrical glass = (22/7) × (3)2 × 8

So we get

Volume of each small cylindrical glass = 226.28 cm3

So the number of small glasses filled = volume of cylindrical vessel/ volume of each glass

By substituting the values

Number of small glasses filled = 22628.571/226.28 = 100

It is given that

Cost of 1 glass = ₹ 15

So the cost of 100 glasses = ₹ (15 × 100) = ₹ 1500

**Therefore, the juice seller receives ₹ 1500 by selling 100 glasses of orange juice.**

ANSWER:

The dimensions of the cylindrical vessel

Radius = 15cm

Height = 32cm

We know that

Volume of cylindrical vessel = πr2h

By substituting the values

Volume of cylindrical vessel = (22/7) × (15)2 × 32

So we get

Volume of cylindrical vessel = 22628.571 cm3

The dimensions of cylindrical glass are

Radius = 3cm

Height = 8cm

We know that

Volume of each small cylindrical glass = πr2h

By substituting the values

Volume of each small cylindrical glass = (22/7) × (3)2 × 8

So we get

Volume of each small cylindrical glass = 226.28 cm3

So the number of small glasses filled = volume of cylindrical vessel/ volume of each glass

By substituting the values

Number of small glasses filled = 22628.571/226.28 = 100

It is given that

Cost of 1 glass = ₹ 15

So the cost of 100 glasses = ₹ (15 × 100) = ₹ 1500

**Therefore, the juice seller receives ₹ 1500 by selling 100 glasses of orange juice.**

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