 # RS Aggarwal Solutions Class 9 Mathematics Solutions for Volume And Surface Area Of Solids Exercise 15B in Chapter 15 - Volume And Surface Area Of Solids

Question 25 Volume And Surface Area Of Solids Exercise 15B

A cylindrical tube, open at both ends, is made of metal. The internal diameter of the tube is 10.4cm and its length is 25cm. The thickness of the metal is 8mm everywhere. Calculate the volume of the metal.

It is given that

Internal diameter of the tube = 10.4cm

Internal radius of the tube = 10.4/ 2 = 5.2 cm

Length = 25cm

We know that

External radius = 5.2 + 0.8 = 6cm

We know that

Required volume = (π × 62 × 25 - π × 5.22 × 25)

Taking the common terms out

Required volume = π × 25 × (62 – 5.22)

On further calculation

Required volume = (22/7) × 25 × (36 – 27.04)

So we get

Required volume = (22/7) × 25 × 8.96 = 704 cm3

Therefore, the volume of the metal is 704 cm3.

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