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RS Aggarwal Solutions Class 9 Mathematics Solutions for Volume And Surface Area Of Solids Exercise 15B in Chapter 15 - Volume And Surface Area Of Solids
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A cylindrical tube, open at both ends, is made of metal. The internal diameter of the tube is 10.4cm and its length is 25cm. The thickness of the metal is 8mm everywhere. Calculate the volume of the metal.
Answer:
ANSWER:
It is given that
Internal diameter of the tube = 10.4cm
Internal radius of the tube = 10.4/ 2 = 5.2 cm
Length = 25cm
We know that
External radius = 5.2 + 0.8 = 6cm
We know that
Required volume = (π × 62 × 25 - π × 5.22 × 25)
Taking the common terms out
Required volume = π × 25 × (62 – 5.22)
On further calculation
Required volume = (22/7) × 25 × (36 – 27.04)
So we get
Required volume = (22/7) × 25 × 8.96 = 704 cm3
Therefore, the volume of the metal is 704 cm3.
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