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RS Aggarwal Solutions Class 9 Mathematics Solutions for Volume And Surface Area Of Solids Exercise 15B in Chapter 15 - Volume And Surface Area Of Solids
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1cm3 of gold is drawn into a wire 0.1mm in diameter. Find the length of the wire.
Answer:
ANSWER:
We know that
1cm3 = 1cm × 1cm × 1cm
1cm = 0.01m
So the volume of gold = 0.01m × 0.01m × 0.01m
We get
Volume of gold = 0.000001m3 ….. (1)
It is given that
Diameter of the wire drawn = 0.1mm
So the radius = 0.1/2 = 0.05mm = 0.00005 m ……. (2)
Consider length of the wire = h m ……. (3)
We know that
Volume of wire drawn = Volume of gold
By substituting the values using (1), (2) and (3)
πr2h = 0.000001
On further calculation
Π × 0.00005 × 0.00005 × h = 0.000001
So we get
h = (0.000001 × 7)/ (0.00005 × 0.00005 × 22) = 127.27m
Therefore, the length of the wire is 127.27m.
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