 # RS Aggarwal Solutions Class 9 Mathematics Solutions for Volume And Surface Area Of Solids Exercise 15A in Chapter 15 - Volume And Surface Area Of Solids

Question 4 Volume And Surface Area Of Solids Exercise 15A

Find the volume, the lateral surface area, and the total surface area of the cuboid whose dimensions are:

length = 24m, breadth = 25cm and height = 6m.

The area of only the curved component of a shape, omitting the base, is referred to as the curved surface area (s).

The region that includes the base (s) and the curving component is referred to as the total surface area. It refers to the whole area of the object's surface.

The volume of an object or substance is the quantity of space that it takes up, measured in cubic units.

It is given that length = 24m, breadth = 25cm = 0.25m and height = 6m

We know that

Volume of cuboid = l × b × h

By substituting the values we get

Volume of cuboid = 24 × 0.25 × 6

By multiplication

Volume of cuboid = 36 m3

We know that

Lateral surface area of a cuboid = 2 (l + b) × h

By substituting the values

Lateral surface area of a cuboid = 2 (24 + 0.25) × 6

On further calculation

Lateral surface area of a cuboid = 2 × 24.25 × 6

By multiplication

Lateral surface area of a cuboid = 291 m2

We know that

Total surface area of cuboid = 2 (lb + bh + lh)

By substituting the values

Total surface area of cuboid = 2 (24 × 0.25 + 0.25 × 6 + 24 × 6)

On further calculation

Total surface area of cuboid = 2 (6 + 1.5 + 144)

So we get

Total surface area of cuboid = 2 × 151.5

By multiplication

Total surface area of cuboid = 303 m2 Related Questions

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