RS Aggarwal Solutions Class 8 Mathematics Solutions for Factorisation Exercise 7E in Chapter 7 - Factorisation

Question 6 Factorisation Exercise 7E

$pq^2+q(p-1)-1=?$

a. (pq+1)(q-1)

b. p(q+1)(q-1)

c. q(p-1)(q+1)

d. (pq-1)(q+1)

Answer:

firstly let's simplify $pq^2+q(p-1)-1=pq^2+qp-q-1$

Now take the common factor as PQ we get,

$\begin{aligned} \mathrm{pq}^{2}+\mathrm{qp}-\mathrm{q}-1 &=\mathrm{pq}(\mathrm{q}+1)-1(\mathrm{q}+1) \\ &=(\mathrm{q}+1)(\mathrm{pq}-1) \end{aligned}$

Related Questions

a) (7a – 9b) (9a + 7b)b) (7a – 9b) (7a + 9b)c) 9(a – 3b) (a + 3b)d) 7(a – 3b) (a + 3b)

a. 2(x-4)(x+4d. 2x(1-4x)(1+4x)

c. x(x-12)(x+12)d. none of these

c. (2-5x)(2+5x)d. 2(1-5x)(1+5x)

a. (a+b)(a+c)b. (a+b)(b+c)c. (b+c)(c+a)d. a(a+b+c)

ab –mn +an –bm = ?a. (a-b) (m-n)b. (a-m) (b+n)c. (a-n) (m+b)d. (m-a) (n-b)

Exercises

Factorisation Exercise 7A

Factorisation Exercise 7B

Factorisation Exercise 7C

Factorisation Exercise 7D

Factorisation Exercise 7E

Chapters

Rational Numbers

Exponents

Squares and Square Roots

Cubes and Cube Roots

Playing with Numbers

Operations on Algebraic Expressions

Factorisation

Linear Equations

Percentage

Profit and Loss

Compound Interest

Direct and Inverse Proportions

Time and Work

Polygons

Parallelograms

Construction of Quadrilaterals

Area of a Trapezium and a Polygon

Three-Dimensional Figures

Volume and Surface Area of Solids

Data Handling

Introduction to Coordinate Geometry

Line Graphs and Linear Graphs

Pie Charts

Probability