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RS Aggarwal Solutions Class 8 Mathematics Solutions for Factorisation Exercise 7E in Chapter 7 - Factorisation

Question 6 Factorisation Exercise 7E

pq^2+q(p-1)-1=?

a. (pq+1)(q-1)

b. p(q+1)(q-1)

c. q(p-1)(q+1)

d. (pq-1)(q+1)

Answer:

firstly let's simplify pq^2+q(p-1)-1=pq^2+qp-q-1

Now take the common factor as PQ we get,

\begin{aligned} \mathrm{pq}^{2}+\mathrm{qp}-\mathrm{q}-1 &=\mathrm{pq}(\mathrm{q}+1)-1(\mathrm{q}+1) \\ &=(\mathrm{q}+1)(\mathrm{pq}-1) \end{aligned}

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