RS Aggarwal Solutions Class 8 Mathematics Solutions for Factorisation Exercise 7E in Chapter 7 - Factorisation

Question 4 Factorisation Exercise 7E

$\left(2-50x^2\right)=?$

$\text{ a. }2(1-5x)^2$

$\text{ b. }2(1+5x)^2$

c. (2-5x)(2+5x)

d. 2(1-5x)(1+5x)

Answer:

let us consider $\left(2-50x^2\right)=2\left(1-25x^2\right)$ by taking 2 as the common factor

By using the formula $a^2-b^2=(a-b)(a+b)$

= 2 (1 – 5x) (1 + 5x)

Video transcript

"hello students i am rita your math leader tutor and the today's question is 2 minus 50 x square is equal to question mark and the option are option a 2 bracket 1 minus 5 x whole square b option 2 bracket 1 plus 5 x whole square c option 2 minus 5 x 2 plus 5 x and the d option 2 bracket 1 minus 5 x and 1 plus 5 x for it is a mcq question and we have to select the correct option now the question is 2 minus 50 x square first of all we take out 2 common from both the numbers then we got 1 minus 25 x square now we can write 1 is a perfect square of 1 and 25 is the perfect square of 5. so we can write it like that and as we know the identity that is e square minus p square is equal to a plus b a minus b now we apply this identity and got the answer that is 1 plus 5 x and 1 minus 5 5x so this is the correct answer it means option d is correct so this is our answer i hope you like this video so please subscribe leto for more updates and do comment your question thank you ."

Related Questions

a) (7a – 9b) (9a + 7b)b) (7a – 9b) (7a + 9b)c) 9(a – 3b) (a + 3b)d) 7(a – 3b) (a + 3b)

a. 2(x-4)(x+4d. 2x(1-4x)(1+4x)

c. x(x-12)(x+12)d. none of these

a. (a+b)(a+c)b. (a+b)(b+c)c. (b+c)(c+a)d. a(a+b+c)

a. (pq+1)(q-1)b. p(q+1)(q-1)c. q(p-1)(q+1)d. (pq-1)(q+1)

ab –mn +an –bm = ?a. (a-b) (m-n)b. (a-m) (b+n)c. (a-n) (m+b)d. (m-a) (n-b)

Exercises

Factorisation Exercise 7A

Factorisation Exercise 7B

Factorisation Exercise 7C

Factorisation Exercise 7D