RS Aggarwal Solutions Class 8 Mathematics Solutions for Factorisation Exercise 7E in Chapter 7 - Factorisation

Question 3 Factorisation Exercise 7E


\text{ a. }x(x-12)^2

\text{ b. }x(x+12)^2

c. x(x-12)(x+12)

d. none of these


let us consider \left(x^{3}-144 x\right)=x\left(x^{2}-144\right.) by taking x as the common factor

By using the formula a^{2}-b^{2}=(a-b)(a+b)

= x (x – 12) (x + 12)

Video transcript
"hello students i am rita your math leader tutor and the today's question is x cube minus 144 x is equal to question mark and the options are a option x bracket x minus 12 whole square b option x bracket x plus 12 whole square and the c option x bracket x minus 12 x plus 12 and the d option none of these it is a mcq question and we have to find the correct option first of all the question is x cube minus 144 x now x we take x is common from both the terms then we got x square minus 144 as we know 100 we can write x square as x whole square and minus 144 is the perfect whole square of 12 so we can write it as 12 square as we know the identity that is a square minus b square is equal to a plus b a minus b now we use this identity in the question and we got the answer so when we use this identity then we got x plus 12 and x minus 12 now this is the answer of this question and the c option is the correct answer so c option is the answer i hope you like this video so please subscribe for more updates and do comment your question thank you "
Connect with us on social media!
2022 © Quality Tutorials Pvt Ltd All rights reserved