(2x+3) (3x-1) =?
(a)\left(6x^2+8x-3\right)
(b)\left(6x^2+7x-3\right)
(c)\left(6x^2-7x-3\right)
(d)\left(6x^2-7x+3\right)
\text{ (b) }\left(6x^2+7x-3\right)
Explanation:
Given (2x+3) (3x-1)
By solving in horizontal method we get
(2x+3) (3x-1)= 2x (3x-1) + 3 (3x-1)
(2x+3)(3x-1)=\left(6x^2+7x-3\right)
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